WebMar 3, 2024 · Option 1 - You control output with FOR JSON PATH In PATH mode, you can use the dot syntax - for example, 'Item.Price' - to format nested output. Here's a sample … WebYou can select multiple values from a json column with CROSS APPLY. SELECT BookId = b.Id, BookTitle = b.Title, CategoryId = c.Id, c.Category, CategoryName = c.Name FROM …
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WebFor Spark 2.1+, you can use from_json which allows the preservation of the other non-json columns within the dataframe as follows: from pyspark.sql.functions import from_json, col json_schema = spark.read.json (df.rdd.map (lambda row: row.json)).schema df.withColumn ('json', from_json (col ('json'), json_schema)) WebMar 12, 2024 · CREATE PROCEDURE parseJSON @DebriefName NVARCHAR (255), @Version INT AS EXEC myProc @DebriefName, @Version; //Need to capture the result data in a temp table or something // Parse the JSON data for each question item in temp table GO; I am not an expert in SQL so not sure how to do this. punta cana kelly tours
JSON_QUERY - Oracle Help Center
WebMar 26, 2024 · You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' (@json, '$ [*]' COLUMNS ( name VARCHAR (40) PATH '$.name', ' at line 1 Just for Information I am using TOAD as tool to connect to my cloud my sql instance. mysql json mysql-5.7 Share Improve this … WebDec 21, 2024 · 2 Answers. Sorted by: 1. It looks like you need to split the value by colon which you can do using Azure Data Factory (ADF) expressions and functions: the split function, which splits a string into an array and the last function to get the last item from the array. This works quite neatly in this case: @last (split (variables ('varWorking'), ':')) WebGenerally it is a bad idea to use spaces in the attribute name. I would leave out the [] from your OPENJSON name and varchar(60) - source MSDN OPENJSON.. Now to actually answer your question: You need to format your attribute with double quotes in the WITH clause: @DECLARE @json NVARCHAR(MAX); SET @json=N'{ "full name" : "Jayesh … punta crena lumassina