Web12 Jun 2013 · The format specifier is wrong. The printf function doesn't know what kind of parameters are passed to it, it can only deduce this from the format specifiers. So when you pass a 64bit integer to it, and tell the function that you passed only a long (32bit) then it takes only half of the 64 bit value passed in. Depending on the architecture, the correct … Websprintf()関数は、一連の文字と値をフォーマット設定し、配列 bufferに保管します。 すべての argument-listは、format-stringの対応する形式指定に従って変換され、出力されます …
[MSVC 2005] printf系で64Bit型整数に気をつけよう - Qiita
WebAhhh, yes, I misunderstood.. Going back and looking at the standard sprintf() function, it does indicate that the destination buffer must be preallocated. I thought sprintf() did the malloc for you. Thanks for the clarification. I should be … WebYou can portably use %jd to print int64_t values if you explicitly convert them to intmax_t before passing them to printf: printf ("a=%jd\n", (intmax_t)a). This avoids the (IMHO) ugliness of the macros. Of course this assumes that your implementation supports %jd, int64_t, and intmax_t, all of which were added by C99. – Keith Thompson spiff e whip dessert topping
C言語 printfのフォーマット指定子 - Qiita
Web12 Aug 2014 · Visual C++2005でunsigned long long などの64bitな値をprintf系関数やcstring::formatで書式化すると妙なことになる場合があったので、バッドノウハウとし … Web关于printf函数输出64位数的问题，其实在window下和linux下是不一样的： linux下是 printf ("%lld/n",a); printf ("%llu/n",a); windows下是 printf ("%I64d/n",a); printf ("%I64u/n",a); 完整程序如下： [zcm@c #51]$cat a.c // linux平台C程序 #include typedef unsigned long long int64; typedef unsigned long long uint64; int main ( void ) { int64 c = 0x123456789LL; // 有 … Web5 May 2024 · nickgammon April 16, 2011, 9:35pm 3. You can use the syntax: long long x; // 64-bit integer long double y; // "long" double? That compiles OK. However a disassembly shows that the "long double", "double" and "float" all generate a … spiff e whip